From the point of view of most of chemistry, atomic, molecular, and condensed-matter (solid, liquid) physics, matter (according to our model) is made up of electrons and (point) nuclei, interacting via electromagnetic forces. That is, nuclei, carrying positive charges attract electrons, which are negatively charged. Electrons repel each other. There are also (much weaker) magnetic interactions, which produce small, but observable, effects. We measure charges and masses of these objects also by using electromagnetic forces. A given chemical element (hydrogen, helium, carbon, aluminum, uranium, etc.) has a position in the periodic table, called its atomic number Z. The atomic number is equal to the number of electrons in the neutral atom, which is the nuclear charge, in units of the electron's charge. This was established by Moseley's systematic study of the x-ray spectra of atoms. In our model, the nucleus consists of Z protons, each with charge equal and opposite to that of the electron and a number N of a neutral particle, the neutron. The total number of nucleons (neutrons and protons) is A = N+Z, usually referred to as the ``atomic weight'' or ``mass number.''
The chemical elements are conveniently organized into a Periodic Table, which we print below. Our table includes the ``Transuranic'' elements (with Z > 92), which were unknown during the early days of ``Modern'' physics.
The format of the periodic table emphasizes its organization by ``shells'', determined by the allowed states and the Pauli Exclusion Principle'', which permits no more than two electrons per orbit. (The electron has an intrinsic ``spin''; One electron spinning clockwise and one spinning counterclockwise may occupy the same orbit.) The shells are labeled by an integer n = 1,2,¼. The maximum number of electrons in shell n is 2·n2, so the first row of the Periodic Table (n = 1) has two (2·12) entries (hydrogen and helium). The second row (n = 2) has eight (2·22) entries (lithium through neon). Each row ends with a rare (or noble) gas, which has a completely filled shell, and is very chemically inert. Complications occur after the second row.
Periodic Table of the elements | |||||||||||||||||
1a | 2a | 3b | 4b | 5b | 6b | 7b | 8 | 1b | 2b | 3a | 4a | 5a | 6a | 7a | 0 | ||
1 | 2 | ||||||||||||||||
H | He | ||||||||||||||||
3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | ||||||||||
Li | Be | B | C | N | O | F | Ne | ||||||||||
11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | ||||||||||
Na | Mg | Al | Si | P | S | Cl | Ar | ||||||||||
19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 | 27 | 28 | 29 | 30 | 31 | 32 | 33 | 34 | 35 | 36 |
K | Ca | Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn | Ga | Ge | As | Se | Br | Kr |
37 | 38 | 39 | 40 | 41 | 42 | 43 | 44 | 45 | 46 | 47 | 48 | 49 | 50 | 51 | 52 | 53 | 54 |
Rb | Sr | Y | Zr | Nb | Mo | Tc | Ru | Rh | Pd | Ag | Cd | In | Sn | Sb | Te | I | Xe |
55 | 56 | 57 | 72 | 73 | 74 | 75 | 76 | 77 | 78 | 79 | 80 | 81 | 82 | 83 | 84 | 85 | 86 |
Cs | Ba | La | Hf | Ta | W | Re | Os | Ir | Pt | Au | Hg | Tl | Pb | Bi | Po | At | Rn |
87 | 88 | 89 | 104 | 105 | 106 | ||||||||||||
Fr | Ra | Ac | Rf | Ha | ?? | ||||||||||||
58 | 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69 | 70 | 71 | ||||
Ce | Pr | Nd | Pm | Sm | Eu | Gd | Tb | Dy | Ho | Er | Tm | Yb | Lu | ||||
90 | 91 | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 | 100 | 101 | 102 | 103 | ||||
Th | Pa | U | Np | Pu | Am | Cm | Bk | Cf | Es | Fm | Md | No | Lr |
A given element may have several isotopes, differing in N. Hydrogen, for example, has 2 stable isotopes 11H (Z = 1,N = 0, ordinary hydrogen), 21H (Z = 1, N = 1, deuterium), and a radioactive isotope 31H (Z = 1, N = 2, tritium). (Tritium does not occur naturally, but will play a rôle in our story.) Helium has 2 stable isotopes 42He (Z = 2, N = 2, ordinary helium or ``helium-4''), 32He (Z = 2, N = 1, ``helium-3''). Here are some atomic masses, taken from the Handbook of Chemistry and Physics.
Some nuclear data | |||
Name | Isotope | nat abund | Mass (amu) |
neutron * | 10n | - | 1.008665 |
hydrogen | 11H | 99.985% | 1.007825 |
deuterium | 21H | 0.015% | 2.0140 |
tritium * | 31H | 0 | 3.01605 |
helium-3 | 32He | 0.00014% | 3.01603 |
helium-4 | 42He | 99.99986% | 4.00260 |
carbon-12 | 612C | 98.89% | 12.00000 (def) |
iron-56 | 5626Fe | 92% | 55.9349 |
krypton-82 | 8236Kr | 11.6% | 81.9136 |
barium-138 | 138 56Ba | 72% | 137.9050 |
uranium-235 * | 235 92U | 0.7% | 235.0439 |
uranium-238 * | 238 92U | 99.3% | 238.0508 |
electron | e or e- | - | 0.0005486 |
The masses are expressed in ``atomic mass units'' (amu), defined so that one carbon-12 atom has a mass of exactly 12 amu. An asterisk denotes a radioactive isotope. The notation is actually redundant, since the chemical symbol and the atomic number Z provide equivalent information. We may sometimes omit the subscript Z.
1.3.1.1 Atoms and molecules The size of atoms and molecules can be determined in several ways, such as:
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The result is that atomic sizes are in the range of a few times 1 Å = 10-10 m (about a hundred thousand times smaller than the width of a hair). Atomic size varies only very slowly through the periodic table. Higher nuclear charge tends to pull the electrons closer to the nucleus; the Pauli Exclusion Principle requires added electron to fill larger orbits. The two effects largely cancel each other.
1.3.1.2 Nuclei The size of the nucleus is much smaller-beyond the reach of microscopies, but its size can be determined by firing projectiles at it (electrons, for example) and studying deviations from what would be expected if the nucleus were a point object. A second method is to compare the binding energy of ``mirror nuclei'' (in which the values of Z and N are exchanged). This difference should be entirely due to electric repulsion, which can be calculated as a function of size.
The result of all these methods is an equation of the form:
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The Binding Energy of an object is the energy necessary to break it up into its constituents. According to Einstein's famous equation
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For example, we can calculate the binding energy of the 4He atom by:
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From our table:
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We can calculate the energy released when one kilogram (1,000 gram or 2.2 lb) of matter is converted to energy by multiplying by the square of the speed of light c » 300,000,000 = 3·108 meter/sec = 186,000 mile/sec. The result is that conversion of 1 kg yields 9·1016 joule, where 1 J=1 kg-m2/s2 = 1 watt-second. We buy electrical energy in units of kilowatt-hours. (1 kW-hr = 1,000 W/kW·3,600 sec/hr = 3.6·106 J will light 10 100 W light bulbs for an hour.) Conversion of 1 kilogram yields more than 1010 kW-hr, enough for a city of one million people for about a year. In our previous example 2n+2p®4He, 4 grams (1 mole) of ``fuel'' will convert 0.0308 gm to energy, yielding 7·1011 J or 1.7·108 kilocalories (kcal). A strong chemical reaction might yield about 100 kcal/mole; we see that the magnitude of energy released is more than a million times greater than in a chemical reaction.
Conversion of 1 amu to energy yields 9·1013/6·1023 = 1.5·10-10J. (6·1023 is the number of atoms in a (gram) mole.) When describing processes at the atomic level, the joule is an inconveniently large unit. Physicists (and Rhodes) often use the electron-volt (eV), the energy acquired when an object with one electronic charge (e = 1.6·10-19coulomb (C)) is accelerated through 1 volt (V). We can convert an energy expressed in J to eV by dividing by e. The energy yielded when 1amu is converted is approximately 9.3·108eV = 930MeV = 0.93GeV.
The energy release in nuclear weapons is frequently given in ``kilotons'' or ``megatons'' (of the chemical explosive TNT). A kiloton is defined to equal 1.0·1012cal = 4.184·10 12J.
We can use the numbers in our table to calculate the binding energy of the several nuclei. The most revealing quantity is the binding energy per nucleon. We calculate it from:
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In the case of 12C, for example:
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Some binding energies | |||||
Isotope | Z | N | A | Mass | BE/nucleon |
21H | 1 | 1 | 2 | 2.014 | 1.15785 |
31H | 1 | 2 | 3 | 3.01605 | 2.82255 |
32He | 2 | 1 | 3 | 3.01603 | 2.56835 |
42He | 2 | 2 | 4 | 4.0026 | 7.06335 |
612C | 6 | 6 | 12 | 12 | 7.66785 |
2311Na | 11 | 12 | 23 | 22.9898 | 8.097267 |
3216S | 16 | 16 | 32 | 31.97207 | 8.479566 |
5626Fe | 26 | 30 | 56 | 55.9349 | 8.776875 |
8236Kr | 36 | 46 | 82 | 81.9136 | 8.695387 |
138 56Ba | 56 | 82 | 138 | 137.905 | 8.381659 |
181 73Ta | 73 | 108 | 181 | 180.948 | 8.010563 |
208 82Pb | 82 | 126 | 208 | 207.9766 | 7.855102 |
235 92U | 92 | 143 | 235 | 235.0439 | 7.578887 |
Here are the data for many nuclides presented in graphical form:
The most strongly-bound nuclei are in the middle of the periodic table, near iron, whose most common isotope 56Fe:
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For 235U:
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The light nuclei are weakly bound because each nucleon is not surrounded by a full complement of neighbors. For the same reason, small droplets of water or mercury will coalesce into a larger droplet, reducing the fraction of the constituent molecules in the surface. These liquids, and the nucleus, have a surface tension.
The weaker binding of the heavy nuclei, and the fact that they contain more neutrons than protons, both arise from the electrical repulsion of the protons. The strong nuclear force between nucleons is attractive, and does not discriminate between the two types of nucleon (n and p.)
Energy is liberated when light nuclei combine (``fusion'') and when heavy nuclei split (``fission'').
If 92238U were to split into two similar fragments, each would have Z = 46, A = 119. The corresponding element is palladium (Pd). Its heaviest stable isotope has A = 110; the heaviest listed radioactive (unstable) isotope has A = 115, and a lifetime of 45 sec. We can see that fission fragments will have too many neutrons for their position in the periodic table. For this reason, they may be expected to emit some neutrons themselves. The figure illustrates this point graphically.
It is this process which leads to the self-sustaining Chain Reaction. We can not directly calculate the energy released in a reaction like
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We can use E = mc2 to calculate the energy released in the entire process leading to stable isotopes. This will include the energy released in the b-decays which will follow the fission. For example, the reaction
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We can estimate the energy released in the fission by another method. Picture the nucleus, having just split into two touching spheres.
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